Brownian Motion

1 selectedDifficulty 8-81 unseenView topic

AdvancedNew

0 answered

1 advancedAdapts to your performance

Question 1 of 1

120sadvanced (8/10)conceptual

Brownian motion (B_{t})_{t \geq 0} has the property that \sum_{i} (B_{t_{i}} - B_{t_{i - 1}})^{2} \to t in L^{2} as the partition mesh of [0, t] goes to 0 . What is the consequence for ordinary Riemann calculus on Brownian paths?